What is the answer to (x-5)^2=|2x-1| ?

The answer to (x-5)^2=|2x-1| is x=6-sqrt(10)\lor x=6+sqrt(10)

Solve for x: (x-5)^2=|2x-1|

The solution is x=6-sqrt(10)\lor x=6+sqrt(10)

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(x - 5)^{2} = ∣ 2 x - 1 ∣

x = 6 - 10 or x = 6 + 10

Decimal

x = 2.83772 \dots, x = 9.16227 \dots

Solution steps

(x - 5)^{2} = ∣ 2 x - 1 ∣

Find positive and negative intervals

x < \frac{1}{2}, x \geq \frac{1}{2}

Solve the inequality for each interval

No Solution or (x = 6 - 10 or x = 6 + 10)

x = 6 - 10 or x = 6 + 10

∣ 5 x + 3 ∣ = 0

2 ∣ 3 x - 3 ∣ 2 x = \frac{1}{12}

∣ 2 x - 3 ∣ + 6 = 2

z^{2} = ∣ z ∣ + 2

∣ 8 x - 1 ∣ - 8 = - 16

What is the answer to (x-5)^2=|2x-1| ?
The answer to (x-5)^2=|2x-1| is x=6-sqrt(10)\lor x=6+sqrt(10)
Solve for x: (x-5)^2=|2x-1|
The solution is x=6-sqrt(10)\lor x=6+sqrt(10)