What are the solutions to the equation c^2=5c ?

The solutions to the equation c^2=5c are c=5,c=0

Find the zeros of c^2=5c

The zeros of c^2=5c are c=5,c=0

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c^{2} = 5 c

c = 5, c = 0

Solution steps

c^{2} = 5 c

Move

5 c

to the left side

c^{2} - 5 c = 0

Solve with the quadratic formula

c_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 0}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 0 = 5

c_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 1}

Separate the solutions

c_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 1}, c_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 1}

c = \frac{- ( - 5 ) + 5}{2 \cdot 1} : 5

c = \frac{- ( - 5 ) - 5}{2 \cdot 1} : 0

The solutions to the quadratic equation are:

c = 5, c = 0

6 y^{2} - 24 y + 18

∣ 2 x + 1 ∣ - 1 > 3

- 12 - 2 = 4 u - 6 u

- 5160 - 5160

- 4 n + 2 n = - 12

What are the solutions to the equation c^2=5c ?
The solutions to the equation c^2=5c are c=5,c=0
Find the zeros of c^2=5c
The zeros of c^2=5c are c=5,c=0