What is the answer to |y^2+3y|=-2y-6 ?

The answer to |y^2+3y|=-2y-6 is y=-3

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|y^2+3y|=-2y-6

y^{2} + 3 y = - 2 y - 6

y = - 3

Solution steps

y^{2} + 3 y = - 2 y - 6

Find positive and negative intervals

y \leq - 3, - 3 < y < 0, y \geq 0

Solve the inequality for each interval

y = - 3 or No Solution

y = - 3

0 = - 4 ∣ x - 6 ∣ - 1

∣ x - 2 ∣ = 3 ∣ x - 2 ∣

∣ x - 3 ∣ + ∣ x - 1 ∣ = 3

x^{2} + 3 = ∣ 2 x + 2 ∣

- 2 - 6 ∣ - 9 x + 7 ∣ = 10