What is the answer to |x^2-5x+6|=10 ?

The answer to |x^2-5x+6|=10 is x=(5-sqrt(41))/2 \lor x=(5+sqrt(41))/2

Solve for x: |x^2-5x+6|=10

The solution is x=(5-sqrt(41))/2 \lor x=(5+sqrt(41))/2

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x^{2} - 5 x + 6 = 10

x = \frac{5 - 41}{2} or x = \frac{5 + 41}{2}

Decimal

x = - 0.70156 \dots, x = 5.70156 \dots

Solution steps

x^{2} - 5 x + 6 = 10

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 5 x + 6 = - 10 or x^{2} - 5 x + 6 = 10

x^{2} - 5 x + 6 = - 10 or x^{2} - 5 x + 6 = 10

No Solution or (x = \frac{5 - 41}{2} or x = \frac{5 + 41}{2})

x = \frac{5 - 41}{2} or x = \frac{5 + 41}{2}

∣ x + 2 ∣ + x^{2} - 3 x + 2 = 4

x^{2} - 2 x = 2

\frac{6 - 2 m}{- 4} - 7 = - 19

∣ 2 x - 4 ∣ - 10 = - 6

∣ x ∣ + 5 = 0

What is the answer to |x^2-5x+6|=10 ?
The answer to |x^2-5x+6|=10 is x=(5-sqrt(41))/2 \lor x=(5+sqrt(41))/2
Solve for x: |x^2-5x+6|=10
The solution is x=(5-sqrt(41))/2 \lor x=(5+sqrt(41))/2