What is the answer to \circ \circ-20+64x=0 ?

The answer to \circ \circ-20+64x=0 is x=(-\circ ^2+20)/(64)

Solve for x: \circ \circ-20+64x=0

The solution is x=(-\circ ^2+20)/(64)

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\circ \circ - 2 0^{\circ} + 64 x = 0

x = \frac{- \circ ^{2} + 2 0 ^{\circ}}{64}

Solution steps

\circ \circ - 2 0^{\circ} + 64 x = 0

Simplify

\circ \circ - 2 0^{\circ} + 64 x : \circ^{2} - 2 0^{\circ} + 64 x

\circ^{2} - 2 0^{\circ} + 64 x = 0

Move

\circ^{2}

to the right side

- 2 0^{\circ} + 64 x = - \circ^{2}

Move

2 0^{\circ}

to the right side

64 x = - \circ^{2} + 2 0^{\circ}

Divide both sides by

64

x = \frac{- \circ ^{2} + 2 0 ^{\circ}}{64}

- 5 < 2 x - 1 \leq 3

10 x^{2} - 64 = 36 + 6 x^{2}

\frac{2}{3} a - \frac{1}{4} a

13.7 x - 8.7 - 14.3 x + 9.4 = - 1.4

14 x^{2} - 39 x - 35

What is the answer to \circ \circ-20+64x=0 ?
The answer to \circ \circ-20+64x=0 is x=(-\circ ^2+20)/(64)
Solve for x: \circ \circ-20+64x=0
The solution is x=(-\circ ^2+20)/(64)