What is the answer to |3x^2-x|=8+x ?

The answer to |3x^2-x|=8+x is x=-4/3 \lor x=2

Solve for x: |3x^2-x|=8+x

The solution is x=-4/3 \lor x=2

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3 x^{2} - x = 8 + x

x = - \frac{4}{3} or x = 2

Decimal

x = - 1.33333 \dots, x = 2

Solution steps

3 x^{2} - x = 8 + x

Find positive and negative intervals

x \leq 0, 0 < x < \frac{1}{3}, x \geq \frac{1}{3}

Solve the inequality for each interval

x = - \frac{4}{3} or No Solution or x = 2

x = - \frac{4}{3} or x = 2

- 4 ∣ k ∣ = 12

∣ 4 x + 1 ∣ = ∣ x + 2 ∣

- 10 - 9 ∣ 3 - x ∣ = - 91

∣ 2 x + 10 ∣ = 0

∣ 6 x - 2 ∣ = ∣ 4 x + 17 ∣

What is the answer to |3x^2-x|=8+x ?
The answer to |3x^2-x|=8+x is x=-4/3 \lor x=2
Solve for x: |3x^2-x|=8+x
The solution is x=-4/3 \lor x=2