What are the solutions to the equation x^2+1x+9=0 ?

The solutions to the equation x^2+1x+9=0 are x=-1/2+i(sqrt(35))/2 ,x=-1/2-i(sqrt(35))/2

Find the zeros of x^2+1x+9=0

The zeros of x^2+1x+9=0 are x=-1/2+i(sqrt(35))/2 ,x=-1/2-i(sqrt(35))/2

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x^{2} + 1 x + 9 = 0

x = - \frac{1}{2} + i \frac{35}{2}, x = - \frac{1}{2} - i \frac{35}{2}

Solution steps

x^{2} + 1 \cdot x + 9 = 0

Refine

x^{2} + x + 9 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 1 \cdot 9}{2 \cdot 1}

Simplify

1^{2} - 4 \cdot 1 \cdot 9 : 35 i

x_{1, 2} = \frac{- 1 \pm 35 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 1 + 35 i}{2 \cdot 1}, x_{2} = \frac{- 1 - 35 i}{2 \cdot 1}

x = \frac{- 1 + 35 i}{2 \cdot 1} : - \frac{1}{2} + i \frac{35}{2}

x = \frac{- 1 - 35 i}{2 \cdot 1} : - \frac{1}{2} - i \frac{35}{2}

The solutions to the quadratic equation are:

x = - \frac{1}{2} + i \frac{35}{2}, x = - \frac{1}{2} - i \frac{35}{2}

50 m = 30 + 0.18 m

4 a^{2} b^{2} + 16 ab + 12 a

\frac{( 3 x - 6 ) ^{2}}{( 2 - x ) ^{2}}

3 x + 9 + 4 x + x = 0 x + 0

256 = 128 t - 16 t^{2}

What are the solutions to the equation x^2+1x+9=0 ?
The solutions to the equation x^2+1x+9=0 are x=-1/2+i(sqrt(35))/2 ,x=-1/2-i(sqrt(35))/2
Find the zeros of x^2+1x+9=0
The zeros of x^2+1x+9=0 are x=-1/2+i(sqrt(35))/2 ,x=-1/2-i(sqrt(35))/2