What is the answer to |1-2x^2|=4 ?

The answer to |1-2x^2|=4 is x=-sqrt(5/2)\lor x=sqrt(5/2)

Solve for x: |1-2x^2|=4

The solution is x=-sqrt(5/2)\lor x=sqrt(5/2)

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1 - 2 x^{2} = 4

x = - \frac{5}{2} or x = \frac{5}{2}

Decimal

x = - 1.58113 \dots, x = 1.58113 \dots

Solution steps

1 - 2 x^{2} = 4

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

1 - 2 x^{2} = - 4 or 1 - 2 x^{2} = 4

1 - 2 x^{2} = - 4 or 1 - 2 x^{2} = 4

(x = - \frac{5}{2} or x = \frac{5}{2}) or No Solution

x = - \frac{5}{2} or x = \frac{5}{2}

\frac{1}{2} ∣ x - 110 ∣ = 6

∣ x - 7 ∣ = ∣ 2 x - 2 ∣

∣ - 7 d - 8 ∣ = 71

y, ∣ x - 180 ∣ = 1.8 y + 90

y, ∣ x + 5 ∣ = y + 2

What is the answer to |1-2x^2|=4 ?
The answer to |1-2x^2|=4 is x=-sqrt(5/2)\lor x=sqrt(5/2)
Solve for x: |1-2x^2|=4
The solution is x=-sqrt(5/2)\lor x=sqrt(5/2)