What is the answer to |x||x+1|=4 ?

The answer to |x||x+1|=4 is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2

Solve for x: |x||x+1|=4

The solution is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2

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∣ x ∣ ∣ x + 1 ∣ = 4

x = \frac{- 1 - 17}{2} or x = \frac{- 1 + 17}{2}

Decimal

x = - 2.56155 \dots, x = 1.56155 \dots

Solution steps

∣ x ∣ ∣ x + 1 ∣ = 4

Find positive and negative intervals

x < - 1, - 1 \leq x < 0, x \geq 0

Solve the inequality for each interval

x = \frac{- 1 - 17}{2} or No Solution or x = \frac{- 1 + 17}{2}

x = \frac{- 1 - 17}{2} or x = \frac{- 1 + 17}{2}

4 ∣ v - 15 ∣ - 6 = 30

x - a

3 ∣ 10 a - 9 ∣ + 7 = 40

∣ 2 x - 5 ∣ = 2 - 3 x

∣ 4 x + 1 ∣ = 10

What is the answer to |x||x+1|=4 ?
The answer to |x||x+1|=4 is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2
Solve for x: |x||x+1|=4
The solution is x=(-1-sqrt(17))/2 \lor x=(-1+sqrt(17))/2