What is the answer to |x^2+1|+|x+1|=2 ?

The answer to |x^2+1|+|x+1|=2 is x=-1\lor x=0

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|x^2+1|+|x+1|=2

x^{2} + 1 + ∣ x + 1 ∣ = 2

x = - 1 or x = 0

Solution steps

x^{2} + 1 + ∣ x + 1 ∣ = 2

Find positive and negative intervals

x < - 1, x \geq - 1

Solve the inequality for each interval

No Solution or (x = - 1 or x = 0)

x = - 1 or x = 0

5 - 4 ∣ 1 + 2 x ∣ = - 3

∣ 3 x ∣ + 3 = 12

∣ 5 x - 4 ∣ = 18

\frac{r}{3} = 5

∣ 8 - 7 b ∣ - 5 = 4

What is the answer to |x^2+1|+|x+1|=2 ?
The answer to |x^2+1|+|x+1|=2 is x=-1\lor x=0
Solve for x: |x^2+1|+|x+1|=2
The solution is x=-1\lor x=0