What is -19|x|+(4x^2-5)<0 ?

The solution to -19|x|+(4x^2-5)<0 is -5<x<5

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-19|x|+(4x^2-5)<0

- 19 ∣ x ∣ + (4 x^{2} - 5) < 0

- 5 < x < 5

Interval Notation

(- 5, 5)

Solution steps

- 19 ∣ x ∣ + 4 x^{2} - 5 < 0

Find positive and negative intervals

x < 0, x \geq 0

Solve the inequality for each interval

- 5 < x < 0 or 0 \leq x < 5

Merge Overlapping Intervals

- 5 < x < 5

2 x^{2} + 8 x - 7 = - 2

4 x^{3} + 12 x^{2} - 16 x - 48

b - 8 > 10

x^{5} - 16 x

30 = 5 (x + 5)