What is the answer to 2|1x+1|-13=0 ?

The answer to 2|1x+1|-13=0 is x=-15/2 \lor x= 11/2

Solve for x: 2|1x+1|-13=0

The solution is x=-15/2 \lor x= 11/2

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2 ∣ 1 x + 1 ∣ - 13 = 0

x = - \frac{15}{2} or x = \frac{11}{2}

Decimal

x = - 7.5, x = 5.5

Solution steps

2 ∣ 1 \cdot x + 1 ∣ - 13 = 0

Move

13

to the right side

2 ∣ 1 x + 1 ∣ = 13

Divide both sides by

2

∣ 1 x + 1 ∣ = \frac{13}{2}

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

1 \cdot x + 1 = - \frac{13}{2} or 1 \cdot x + 1 = \frac{13}{2}

1 x + 1 = - \frac{13}{2} or 1 x + 1 = \frac{13}{2}

x = - \frac{15}{2} or x = \frac{11}{2}

d, ∣ d + 2 ∣ + 7 = 7

∣ u + 1 ∣ = 2

∣ - 3 x + 4 ∣ = 16

∣ c - 3 ∣ = 1

- 3 ∣ x - 1 ∣ + 2 = 0

What is the answer to 2|1x+1|-13=0 ?
The answer to 2|1x+1|-13=0 is x=-15/2 \lor x= 11/2
Solve for x: 2|1x+1|-13=0
The solution is x=-15/2 \lor x= 11/2