What are the solutions to the equation x^2-6x+12=4 ?

The solutions to the equation x^2-6x+12=4 are x=4,x=2

Find the zeros of x^2-6x+12=4

The zeros of x^2-6x+12=4 are x=4,x=2

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x^{2} - 6 x + 12 = 4

x = 4, x = 2

Solution steps

x^{2} - 6 x + 12 = 4

Move

4

to the left side

x^{2} - 6 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 8 = 2

x_{1, 2} = \frac{- ( - 6 ) \pm 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2}{2 \cdot 1} : 4

x = \frac{- ( - 6 ) - 2}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 4, x = 2

∣ - 6 b ∣ \leq 60

\frac{5 + i}{- 6 - 2 i}

3 x^{2} y^{4} + 6 x^{3} y^{3}

n^{0}

2 x^{2} - 6 x + 9 = 0

What are the solutions to the equation x^2-6x+12=4 ?
The solutions to the equation x^2-6x+12=4 are x=4,x=2
Find the zeros of x^2-6x+12=4
The zeros of x^2-6x+12=4 are x=4,x=2