What is the answer to |2k+5|=2sqrt(k^2+2^2) ?

The answer to |2k+5|=2sqrt(k^2+2^2) is k=-9/20

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|2k+5|=2sqrt(k^2+2^2)

∣ 2 k + 5 ∣ = 2 k^{2} + 2^{2}

k = - \frac{9}{20}

Decimal

k = - 0.45

Solution steps

∣ 2 k + 5 ∣ = 2 k^{2} + 2^{2}

Find positive and negative intervals

k < - \frac{5}{2}, k \geq - \frac{5}{2}

Solve the inequality for each interval

No Solution or k = - \frac{9}{20}

k = - \frac{9}{20}

∣ - 2 x - 6 ∣ = 2

∣ 4 a + 10 ∣ = 12

3 ∣ x + 2 ∣ - 9 = 0

y, ∣ x ∣ + y = 0

2 x - 3 ∣ x - 1 ∣ + 1 = 0

What is the answer to |2k+5|=2sqrt(k^2+2^2) ?
The answer to |2k+5|=2sqrt(k^2+2^2) is k=-9/20
Solve for k: |2k+5|=2sqrt(k^2+2^2)
The solution is k=-9/20