What are the solutions to the equation x^4-3x^2+2=0 ?

The solutions to the equation x^4-3x^2+2=0 are x=sqrt(2),x=-sqrt(2),x=1,x=-1

Find the zeros of x^4-3x^2+2=0

The zeros of x^4-3x^2+2=0 are x=sqrt(2),x=-sqrt(2),x=1,x=-1

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x^{4} - 3 x^{2} + 2 = 0

x = 2, x = - 2, x = 1, x = - 1

Decimal Notation

x = 1.41421 \dots, x = - 1.41421 \dots, x = 1, x = - 1

Solution steps

x^{4} - 3 x^{2} + 2 = 0

Rewrite the equation with

u = x^{2}

and

u^{2} = x^{4}

u^{2} - 3 u + 2 = 0

Solve

u^{2} - 3 u + 2 = 0 : u = 2, u = 1

u = 2, u = 1

Substitute back

u = x^{2},

solve for

x

Solve

x^{2} = 2 : x = 2, x = - 2

Solve

x^{2} = 1 : x = 1, x = - 1

The solutions are

x = 2, x = - 2, x = 1, x = - 1

\frac{1}{3} x - 15 = x - 5

∣ 5 m - 9 ∣ \geq 24

\frac{y}{5} + \frac{y}{3} = 8

5 (x - 3) = 5 (4 x + 3)

y + 9 = - 21

What are the solutions to the equation x^4-3x^2+2=0 ?
The solutions to the equation x^4-3x^2+2=0 are x=sqrt(2),x=-sqrt(2),x=1,x=-1
Find the zeros of x^4-3x^2+2=0
The zeros of x^4-3x^2+2=0 are x=sqrt(2),x=-sqrt(2),x=1,x=-1