What are the solutions to the equation x^2+18x+78=0 ?

The solutions to the equation x^2+18x+78=0 are x=-9+sqrt(3),x=-9-sqrt(3)

Find the zeros of x^2+18x+78=0

The zeros of x^2+18x+78=0 are x=-9+sqrt(3),x=-9-sqrt(3)

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x^{2} + 18 x + 78 = 0

x = - 9 + 3, x = - 9 - 3

Solution steps

x^{2} + 18 x + 78 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 18 \pm 1 8 ^{2} - 4 \cdot 1 \cdot 78}{2 \cdot 1}

1 8^{2} - 4 \cdot 1 \cdot 78 = 23

x_{1, 2} = \frac{- 18 \pm 2 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 18 + 2 3}{2 \cdot 1}, x_{2} = \frac{- 18 - 2 3}{2 \cdot 1}

x = \frac{- 18 + 2 3}{2 \cdot 1} : - 9 + 3

x = \frac{- 18 - 2 3}{2 \cdot 1} : - 9 - 3

The solutions to the quadratic equation are:

x = - 9 + 3, x = - 9 - 3

(\frac{- 8}{2})^{2}

e^{- \frac{1}{x}}

- x^{2} - 3 x + 4 = 0

3 < 4 s - 1

2 x^{2} - x - 5 = 0

What are the solutions to the equation x^2+18x+78=0 ?
The solutions to the equation x^2+18x+78=0 are x=-9+sqrt(3),x=-9-sqrt(3)
Find the zeros of x^2+18x+78=0
The zeros of x^2+18x+78=0 are x=-9+sqrt(3),x=-9-sqrt(3)