What are the solutions to the equation quadraticformula x^2-3x=-2 ?

The solutions to the equation quadraticformula x^2-3x=-2 are x=2,x=1

Find the zeros of quadraticformula x^2-3x=-2

The zeros of quadraticformula x^2-3x=-2 are x=2,x=1

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x^{2} - 3 x = - 2

x = 2, x = 1

Solution steps

x^{2} - 3 x = - 2

Move

2

to the left side

x^{2} - 3 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 3 ) \pm ( - 3 ) ^{2} - 4 \cdot 1 \cdot 2}{2 \cdot 1}

(- 3)^{2} - 4 \cdot 1 \cdot 2 = 1

x_{1, 2} = \frac{- ( - 3 ) \pm 1}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 3 ) + 1}{2 \cdot 1}, x_{2} = \frac{- ( - 3 ) - 1}{2 \cdot 1}

x = \frac{- ( - 3 ) + 1}{2 \cdot 1} : 2

x = \frac{- ( - 3 ) - 1}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 2, x = 1

- x^{2} - 13 x - 40

32/8

x, ∣ x ∣ = 4

x, ∣ x - 4 ∣ = 2

\frac{3}{7}

What are the solutions to the equation quadraticformula x^2-3x=-2 ?
The solutions to the equation quadraticformula x^2-3x=-2 are x=2,x=1
Find the zeros of quadraticformula x^2-3x=-2
The zeros of quadraticformula x^2-3x=-2 are x=2,x=1