What are the solutions to the equation quadraticformula x^2-5x-1=0 ?

The solutions to the equation quadraticformula x^2-5x-1=0 are x=(5+sqrt(29))/2 ,x=(5-sqrt(29))/2

Find the zeros of quadraticformula x^2-5x-1=0

The zeros of quadraticformula x^2-5x-1=0 are x=(5+sqrt(29))/2 ,x=(5-sqrt(29))/2

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x^{2} - 5 x - 1 = 0

x = \frac{5 + 29}{2}, x = \frac{5 - 29}{2}

Solution steps

x^{2} - 5 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 1 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 1) = 29

x_{1, 2} = \frac{- ( - 5 ) \pm 29}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 29}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 29}{2 \cdot 1}

x = \frac{- ( - 5 ) + 29}{2 \cdot 1} : \frac{5 + 29}{2}

x = \frac{- ( - 5 ) - 29}{2 \cdot 1} : \frac{5 - 29}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 29}{2}, x = \frac{5 - 29}{2}

\frac{( x ^{5} )}{( x ^{3} )}

\frac{12}{( 3 )}

\frac{17}{2}

\frac{4}{36}

\frac{6}{( 2 )}

What are the solutions to the equation quadraticformula x^2-5x-1=0 ?
The solutions to the equation quadraticformula x^2-5x-1=0 are x=(5+sqrt(29))/2 ,x=(5-sqrt(29))/2
Find the zeros of quadraticformula x^2-5x-1=0
The zeros of quadraticformula x^2-5x-1=0 are x=(5+sqrt(29))/2 ,x=(5-sqrt(29))/2