What are the solutions to the equation quadraticformula x^2-5x=-4 ?

The solutions to the equation quadraticformula x^2-5x=-4 are x=4,x=1

Find the zeros of quadraticformula x^2-5x=-4

The zeros of quadraticformula x^2-5x=-4 are x=4,x=1

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x^{2} - 5 x = - 4

x = 4, x = 1

Solution steps

x^{2} - 5 x = - 4

Move

4

to the left side

x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot 4}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot 4 = 3

x_{1, 2} = \frac{- ( - 5 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 3}{2 \cdot 1}

x = \frac{- ( - 5 ) + 3}{2 \cdot 1} : 4

x = \frac{- ( - 5 ) - 3}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 4, x = 1

- x^{2} + 12 x - 35

(0.5) \cdot 3

x, 4 x = 7

d, 10 d - 6 d = 4

x^{2} + 10 x - 24 = 0

What are the solutions to the equation quadraticformula x^2-5x=-4 ?
The solutions to the equation quadraticformula x^2-5x=-4 are x=4,x=1
Find the zeros of quadraticformula x^2-5x=-4
The zeros of quadraticformula x^2-5x=-4 are x=4,x=1