What is x^3-7=0,a=2 ?

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Find the Root Using Newton's Method x^3-7=0 , a=2

x^{3} - 7 = 0, a = 2

Solution steps

[x^{3} - 7 = 0 a = 2]

Solve

For

a = 2

, subsitute

x

with

For

a = 2

, subsitute

x

with

For

a = 2

, subsitute

x

with

Verify solutions by plugging them into the original equations

Therefore, the final solutions for

x^{3} - 7 = 0, a = 2

are

5 w^{2} - 3 = 0

- 12/6

x, 2 x - 2 = 0

(3 x - 5) (x + 3)

h, V = \frac{1}{3 p i r ^{2} h}