What are the solutions to the equation solvefor x,x^2-x-4=0 ?

The solutions to the equation solvefor x,x^2-x-4=0 are x=(1+sqrt(17))/2 ,x=(1-sqrt(17))/2

Find the zeros of solvefor x,x^2-x-4=0

The zeros of solvefor x,x^2-x-4=0 are x=(1+sqrt(17))/2 ,x=(1-sqrt(17))/2

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x, x^{2} - x - 4 = 0

x = \frac{1 + 17}{2}, x = \frac{1 - 17}{2}

Solution steps

x^{2} - x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 1)^{2} - 4 \cdot 1 \cdot (- 4) = 17

x_{1, 2} = \frac{- ( - 1 ) \pm 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 17}{2 \cdot 1}, x_{2} = \frac{- ( - 1 ) - 17}{2 \cdot 1}

x = \frac{- ( - 1 ) + 17}{2 \cdot 1} : \frac{1 + 17}{2}

x = \frac{- ( - 1 ) - 17}{2 \cdot 1} : \frac{1 - 17}{2}

The solutions to the quadratic equation are:

x = \frac{1 + 17}{2}, x = \frac{1 - 17}{2}

40% o f 70

x, - 5 = 3 x - 2

a, a - (- 6) = 12

x, 5 - x = 12

What are the solutions to the equation solvefor x,x^2-x-4=0 ?
The solutions to the equation solvefor x,x^2-x-4=0 are x=(1+sqrt(17))/2 ,x=(1-sqrt(17))/2
Find the zeros of solvefor x,x^2-x-4=0
The zeros of solvefor x,x^2-x-4=0 are x=(1+sqrt(17))/2 ,x=(1-sqrt(17))/2