What is longdivision ((24x^3-14x^2+20x+6))/((4x^2-3x+5)) ?

The solution to longdivision ((24x^3-14x^2+20x+6))/((4x^2-3x+5)) is 6x+1+(-7x+1)/(4x^2-3x+5)

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Divide Using Long Polynomial Division (24x^3-14x^2+20x+6)÷(4x^2-3x+5)

long division

\frac{( 24 x ^{3} - 14 x ^{2} + 20 x + 6 )}{( 4 x ^{2} - 3 x + 5 )}

6 x + 1 + \frac{- 7 x + 1}{4 x ^{2} - 3 x + 5}

Solution steps

\frac{( 24 x ^{3} - 14 x ^{2} + 20 x + 6 )}{( 4 x ^{2} - 3 x + 5 )}

Divide

\frac{24 x ^{3} - 14 x ^{2} + 20 x + 6}{4 x ^{2} - 3 x + 5} : \frac{24 x ^{3} - 14 x ^{2} + 20 x + 6}{4 x ^{2} - 3 x + 5} = 6 x + \frac{4 x ^{2} - 10 x + 6}{4 x ^{2} - 3 x + 5}

= 6 x + \frac{4 x ^{2} - 10 x + 6}{4 x ^{2} - 3 x + 5}

Divide

\frac{4 x ^{2} - 10 x + 6}{4 x ^{2} - 3 x + 5} : \frac{4 x ^{2} - 10 x + 6}{4 x ^{2} - 3 x + 5} = 1 + \frac{- 7 x + 1}{4 x ^{2} - 3 x + 5}

= 6 x + 1 + \frac{- 7 x + 1}{4 x ^{2} - 3 x + 5}

15 x

x, 6 x - 1 = 3

- 5 y

\frac{( 52 )}{( 12 )}

x, x^{2} - 5 x = 14

What is longdivision ((24x^3-14x^2+20x+6))/((4x^2-3x+5)) ?
The solution to longdivision ((24x^3-14x^2+20x+6))/((4x^2-3x+5)) is 6x+1+(-7x+1)/(4x^2-3x+5)