What are the solutions to the equation quadraticformula x^2+6x=16 ?

The solutions to the equation quadraticformula x^2+6x=16 are x=2,x=-8

Find the zeros of quadraticformula x^2+6x=16

The zeros of quadraticformula x^2+6x=16 are x=2,x=-8

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} + 6 x = 16

x = 2, x = - 8

Solution steps

x^{2} + 6 x = 16

Move

16

to the left side

x^{2} + 6 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 16) = 10

x_{1, 2} = \frac{- 6 \pm 10}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 10}{2 \cdot 1}, x_{2} = \frac{- 6 - 10}{2 \cdot 1}

x = \frac{- 6 + 10}{2 \cdot 1} : 2

x = \frac{- 6 - 10}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 2, x = - 8

60/10

x, \frac{( x - 3 )}{4} = \frac{x}{2}

4 \times (5)

120/15

\frac{50}{8}

What are the solutions to the equation quadraticformula x^2+6x=16 ?
The solutions to the equation quadraticformula x^2+6x=16 are x=2,x=-8
Find the zeros of quadraticformula x^2+6x=16
The zeros of quadraticformula x^2+6x=16 are x=2,x=-8