What are the solutions to the equation quadraticformula x^2-6x-10=0 ?

The solutions to the equation quadraticformula x^2-6x-10=0 are x=3+sqrt(19),x=3-sqrt(19)

Find the zeros of quadraticformula x^2-6x-10=0

The zeros of quadraticformula x^2-6x-10=0 are x=3+sqrt(19),x=3-sqrt(19)

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x^{2} - 6 x - 10 = 0

x = 3 + 19, x = 3 - 19

Decimal Notation

x = 7.35889 \dots, x = - 1.35889 \dots

Solution steps

x^{2} - 6 x - 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 10) = 219

x_{1, 2} = \frac{- ( - 6 ) \pm 2 19}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 19}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 2 19}{2 \cdot 1}

x = \frac{- ( - 6 ) + 2 19}{2 \cdot 1} : 3 + 19

x = \frac{- ( - 6 ) - 2 19}{2 \cdot 1} : 3 - 19

The solutions to the quadratic equation are:

x = 3 + 19, x = 3 - 19

x, 2 x - 3 = 7

\frac{1}{( cos ( θ ) )}

\frac{( 54 )}{( 3 )}

x, - 3 x - 8 = 10

\frac{( 11 ! )}{( 8 ! )}

What are the solutions to the equation quadraticformula x^2-6x-10=0 ?
The solutions to the equation quadraticformula x^2-6x-10=0 are x=3+sqrt(19),x=3-sqrt(19)
Find the zeros of quadraticformula x^2-6x-10=0
The zeros of quadraticformula x^2-6x-10=0 are x=3+sqrt(19),x=3-sqrt(19)