What is expand 3x^2(2xy-3xy^2+4x^2y^3) ?

The solution to expand 3x^2(2xy-3xy^2+4x^2y^3) is 6x^3y-9x^3y^2+12x^4y^3

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Simplify 3x^2(2xy-3xy^2+4x^2y^3)

expand

3 x^{2} (2 x y - 3 x y^{2} + 4 x^{2} y^{3})

6 x^{3} y - 9 x^{3} y^{2} + 12 x^{4} y^{3}

Solution steps

3 x^{2} (2 x y - 3 x y^{2} + 4 x^{2} y^{3})

Apply the distributive law:

m (a + b + c) = ma + mb + m c

3 x^{2} (2 x y - 3 x y^{2} + 4 x^{2} y^{3}) = 3 x^{2} \cdot 2 x y + 3 x^{2} (- 3 x y^{2}) + 3 x^{2} \cdot 4 x^{2} y^{3}

= 3 x^{2} \cdot 2 x y + 3 x^{2} (- 3 x y^{2}) + 3 x^{2} \cdot 4 x^{2} y^{3}

Simplify

3 x^{2} \cdot 2 x y + 3 x^{2} (- 3 x y^{2}) + 3 x^{2} \cdot 4 x^{2} y^{3} : 6 x^{3} y - 9 x^{3} y^{2} + 12 x^{4} y^{3}

= 6 x^{3} y - 9 x^{3} y^{2} + 12 x^{4} y^{3}

\frac{( 12 ! )}{( 8 ! )}

x^{2} - 12 x = - 36

0.02%

27 x^{2}

x, 3 x = 8

What is expand 3x^2(2xy-3xy^2+4x^2y^3) ?
The solution to expand 3x^2(2xy-3xy^2+4x^2y^3) is 6x^3y-9x^3y^2+12x^4y^3