What are the solutions to the equation quadraticformula x^2-8x-16=0 ?

The solutions to the equation quadraticformula x^2-8x-16=0 are x=4(1+sqrt(2)),x=4(1-sqrt(2))

Find the zeros of quadraticformula x^2-8x-16=0

The zeros of quadraticformula x^2-8x-16=0 are x=4(1+sqrt(2)),x=4(1-sqrt(2))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 8 x - 16 = 0

x = 4 (1 + 2), x = 4 (1 - 2)

Decimal Notation

x = 9.65685 \dots, x = - 1.65685 \dots

Solution steps

x^{2} - 8 x - 16 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 16 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 16) = 82

x_{1, 2} = \frac{- ( - 8 ) \pm 8 2}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 8 2}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 8 2}{2 \cdot 1}

x = \frac{- ( - 8 ) + 8 2}{2 \cdot 1} : 4 (1 + 2)

x = \frac{- ( - 8 ) - 8 2}{2 \cdot 1} : 4 (1 - 2)

The solutions to the quadratic equation are:

x = 4 (1 + 2), x = 4 (1 - 2)

3.2%

x, 2 x - 1 = 7

2 x \cdot (3 x)

x^{2} - 7 x = - 6

1.2 5^{5}

What are the solutions to the equation quadraticformula x^2-8x-16=0 ?
The solutions to the equation quadraticformula x^2-8x-16=0 are x=4(1+sqrt(2)),x=4(1-sqrt(2))
Find the zeros of quadraticformula x^2-8x-16=0
The zeros of quadraticformula x^2-8x-16=0 are x=4(1+sqrt(2)),x=4(1-sqrt(2))