What are the solutions to the equation x^2-5x-5=2x+3 ?

The solutions to the equation x^2-5x-5=2x+3 are x=8,x=-1

Find the zeros of x^2-5x-5=2x+3

The zeros of x^2-5x-5=2x+3 are x=8,x=-1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^{2} - 5 x - 5 = 2 x + 3

x = 8, x = - 1

Solution steps

x^{2} - 5 x - 5 = 2 x + 3

Move

3

to the left side

x^{2} - 5 x - 8 = 2 x

Move

2 x

to the left side

x^{2} - 7 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 8 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 8) = 9

x_{1, 2} = \frac{- ( - 7 ) \pm 9}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 9}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 9}{2 \cdot 1}

x = \frac{- ( - 7 ) + 9}{2 \cdot 1} : 8

x = \frac{- ( - 7 ) - 9}{2 \cdot 1} : - 1

The solutions to the quadratic equation are:

x = 8, x = - 1

h, 3 h = 7 (\frac{2}{7} - \frac{3}{7} h) - 10

x, ∣ 3 x - 4 ∣ = ∣ 3 x - 5 ∣

144/24

- 132/11

192 x^{2}

What are the solutions to the equation x^2-5x-5=2x+3 ?
The solutions to the equation x^2-5x-5=2x+3 are x=8,x=-1
Find the zeros of x^2-5x-5=2x+3
The zeros of x^2-5x-5=2x+3 are x=8,x=-1