What are the solutions to the equation quadraticformula x^2-12x-32 ?

The solutions to the equation quadraticformula x^2-12x-32 are x=2(3+sqrt(17)),x=2(3-sqrt(17))

Find the zeros of quadraticformula x^2-12x-32

The zeros of quadraticformula x^2-12x-32 are x=2(3+sqrt(17)),x=2(3-sqrt(17))

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quadratic formula

x^{2} - 12 x - 32

x = 2 (3 + 17), x = 2 (3 - 17)

Solution steps

x^{2} - 12 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 1 \cdot ( - 32 )}{2 \cdot 1}

(- 12)^{2} - 4 \cdot 1 \cdot (- 32) = 417

x_{1, 2} = \frac{- ( - 12 ) \pm 4 17}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 12 ) + 4 17}{2 \cdot 1}, x_{2} = \frac{- ( - 12 ) - 4 17}{2 \cdot 1}

x = \frac{- ( - 12 ) + 4 17}{2 \cdot 1} : 2 (3 + 17)

x = \frac{- ( - 12 ) - 4 17}{2 \cdot 1} : 2 (3 - 17)

The solutions to the quadratic equation are:

x = 2 (3 + 17), x = 2 (3 - 17)

\frac{64}{9}

\frac{29}{4}

65%

x, x^{2} = 36

\frac{81}{5}

What are the solutions to the equation quadraticformula x^2-12x-32 ?
The solutions to the equation quadraticformula x^2-12x-32 are x=2(3+sqrt(17)),x=2(3-sqrt(17))
Find the zeros of quadraticformula x^2-12x-32
The zeros of quadraticformula x^2-12x-32 are x=2(3+sqrt(17)),x=2(3-sqrt(17))