What are the solutions to the equation quadraticformula x^2-2x-80=0 ?

The solutions to the equation quadraticformula x^2-2x-80=0 are x=10,x=-8

Find the zeros of quadraticformula x^2-2x-80=0

The zeros of quadraticformula x^2-2x-80=0 are x=10,x=-8

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x^{2} - 2 x - 80 = 0

x = 10, x = - 8

Solution steps

x^{2} - 2 x - 80 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 80 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 80) = 18

x_{1, 2} = \frac{- ( - 2 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 18}{2 \cdot 1}

x = \frac{- ( - 2 ) + 18}{2 \cdot 1} : 10

x = \frac{- ( - 2 ) - 18}{2 \cdot 1} : - 8

The solutions to the quadratic equation are:

x = 10, x = - 8

2 x - 7

60 = 15

5 x + 12 = 0

x^{2} = 9 x - 20

42/14

What are the solutions to the equation quadraticformula x^2-2x-80=0 ?
The solutions to the equation quadraticformula x^2-2x-80=0 are x=10,x=-8
Find the zeros of quadraticformula x^2-2x-80=0
The zeros of quadraticformula x^2-2x-80=0 are x=10,x=-8