What are the solutions to the equation factor x^2-x=12 ?

The solutions to the equation factor x^2-x=12 are x=-3,x=4

Find the zeros of factor x^2-x=12

The zeros of factor x^2-x=12 are x=-3,x=4

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x^{2} - x = 12

x = - 3, x = 4

Solution steps

x^{2} - x = 12

Move

12

to the left side

x^{2} - x - 12 = 0

Factor

x^{2} - x - 12 : (x + 3) (x - 4)

(x + 3) (x - 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 3 = 0 or x - 4 = 0

Solve

x + 3 = 0 : x = - 3

Solve

x - 4 = 0 : x = 4

The solutions to the quadratic equation are:

x = - 3, x = 4

x, 12 - x > 15

x^{2} + 5 x - 12 = 0

\frac{( x ^{6} )}{( x ^{2} )}

(- 7) (- 15)

(1.05)^{\frac{1}{2}}

What are the solutions to the equation factor x^2-x=12 ?
The solutions to the equation factor x^2-x=12 are x=-3,x=4
Find the zeros of factor x^2-x=12
The zeros of factor x^2-x=12 are x=-3,x=4