What are the solutions to the equation quadraticformula x^2-24=0 ?

The solutions to the equation quadraticformula x^2-24=0 are x=2sqrt(6),x=-2sqrt(6)

Find the zeros of quadraticformula x^2-24=0

The zeros of quadraticformula x^2-24=0 are x=2sqrt(6),x=-2sqrt(6)

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x^{2} - 24 = 0

x = 26, x = - 26

Decimal Notation

x = 4.89897 \dots, x = - 4.89897 \dots

Solution steps

x^{2} - 24 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 0 \pm 0 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

0^{2} - 4 \cdot 1 \cdot (- 24) = 46

x_{1, 2} = \frac{- 0 \pm 4 6}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 0 + 4 6}{2 \cdot 1}, x_{2} = \frac{- 0 - 4 6}{2 \cdot 1}

x = \frac{- 0 + 4 6}{2 \cdot 1} : 26

x = \frac{- 0 - 4 6}{2 \cdot 1} : - 26

The solutions to the quadratic equation are:

x = 26, x = - 26

s, 2 - 2 s = \frac{3}{4 s + 13}

8 x^{2} - 7 x + 2 + (3 x^{2} - 9 x - 6)

\frac{( 2 )}{( 34 )}

- \frac{12}{24}

r, \frac{1}{3} + \frac{5}{3} r - r = 2 r

What are the solutions to the equation quadraticformula x^2-24=0 ?
The solutions to the equation quadraticformula x^2-24=0 are x=2sqrt(6),x=-2sqrt(6)
Find the zeros of quadraticformula x^2-24=0
The zeros of quadraticformula x^2-24=0 are x=2sqrt(6),x=-2sqrt(6)