What are the solutions to the equation quadraticformula 2x^2-5x-12=0 ?

The solutions to the equation quadraticformula 2x^2-5x-12=0 are x=4,x=-3/2

Find the zeros of quadraticformula 2x^2-5x-12=0

The zeros of quadraticformula 2x^2-5x-12=0 are x=4,x=-3/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - 5 x - 12 = 0

x = 4, x = - \frac{3}{2}

Decimal Notation

x = 4, x = - 1.5

Solution steps

2 x^{2} - 5 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 5)^{2} - 4 \cdot 2 (- 12) = 11

x_{1, 2} = \frac{- ( - 5 ) \pm 11}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 11}{2 \cdot 2}, x_{2} = \frac{- ( - 5 ) - 11}{2 \cdot 2}

x = \frac{- ( - 5 ) + 11}{2 \cdot 2} : 4

x = \frac{- ( - 5 ) - 11}{2 \cdot 2} : - \frac{3}{2}

The solutions to the quadratic equation are:

x = 4, x = - \frac{3}{2}

(20)^{0}

42 - 8

1 6^{- 1} 0.5

x, ∣ 2 x ∣ = 6

102

What are the solutions to the equation quadraticformula 2x^2-5x-12=0 ?
The solutions to the equation quadraticformula 2x^2-5x-12=0 are x=4,x=-3/2
Find the zeros of quadraticformula 2x^2-5x-12=0
The zeros of quadraticformula 2x^2-5x-12=0 are x=4,x=-3/2