What are the solutions to the equation quadraticformula x^2-2x=99 ?

The solutions to the equation quadraticformula x^2-2x=99 are x=11,x=-9

Find the zeros of quadraticformula x^2-2x=99

The zeros of quadraticformula x^2-2x=99 are x=11,x=-9

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x^{2} - 2 x = 99

x = 11, x = - 9

Solution steps

x^{2} - 2 x = 99

Move

99

to the left side

x^{2} - 2 x - 99 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 1 \cdot ( - 99 )}{2 \cdot 1}

(- 2)^{2} - 4 \cdot 1 \cdot (- 99) = 20

x_{1, 2} = \frac{- ( - 2 ) \pm 20}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 20}{2 \cdot 1}, x_{2} = \frac{- ( - 2 ) - 20}{2 \cdot 1}

x = \frac{- ( - 2 ) + 20}{2 \cdot 1} : 11

x = \frac{- ( - 2 ) - 20}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 11, x = - 9

1.5%

12 x^{2}

t, 3 t + 7 = - 8

e^{- 1} 0.4

2 x

What are the solutions to the equation quadraticformula x^2-2x=99 ?
The solutions to the equation quadraticformula x^2-2x=99 are x=11,x=-9
Find the zeros of quadraticformula x^2-2x=99
The zeros of quadraticformula x^2-2x=99 are x=11,x=-9