What is the answer to |x^2-2x-16|=8 ?

The answer to |x^2-2x-16|=8 is x=-4\lor x=-2\lor x=4\lor x=6

Solve for x: |x^2-2x-16|=8

The solution is x=-4\lor x=-2\lor x=4\lor x=6

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x^{2} - 2 x - 16 = 8

x = - 4 or x = - 2 or x = 4 or x = 6

Solution steps

x^{2} - 2 x - 16 = 8

Apply absolute rule: If

∣ u ∣ = a, a > 0

then

u = a

u = - a

x^{2} - 2 x - 16 = - 8 or x^{2} - 2 x - 16 = 8

x^{2} - 2 x - 16 = - 8 or x^{2} - 2 x - 16 = 8

(x = - 2 or x = 4) or (x = - 4 or x = 6)

x = - 4 or x = - 2 or x = 4 or x = 6

5 (x + 1) = 3 x + 2 (x + 1) + 4

- 1 \leq 4 x + 3 < 11

x^{3} - 7 x - 6 > 0

x y^{2} - b y^{2} - a x + ab + y^{2} - a

3 - x \geq 5 (3 - x)

What is the answer to |x^2-2x-16|=8 ?
The answer to |x^2-2x-16|=8 is x=-4\lor x=-2\lor x=4\lor x=6
Solve for x: |x^2-2x-16|=8
The solution is x=-4\lor x=-2\lor x=4\lor x=6