What are the solutions to the equation quadraticformula x^2+15x+50=0 ?

The solutions to the equation quadraticformula x^2+15x+50=0 are x=-5,x=-10

Find the zeros of quadraticformula x^2+15x+50=0

The zeros of quadraticformula x^2+15x+50=0 are x=-5,x=-10

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x^{2} + 15 x + 50 = 0

x = - 5, x = - 10

Solution steps

x^{2} + 15 x + 50 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 \cdot 1 \cdot 50}{2 \cdot 1}

1 5^{2} - 4 \cdot 1 \cdot 50 = 5

x_{1, 2} = \frac{- 15 \pm 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 15 + 5}{2 \cdot 1}, x_{2} = \frac{- 15 - 5}{2 \cdot 1}

x = \frac{- 15 + 5}{2 \cdot 1} : - 5

x = \frac{- 15 - 5}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

x = - 5, x = - 10

79

30%

- 180/15

3 \frac{1}{4} - 1 \frac{3}{4}

\frac{9}{( x ^{- 4} )}

What are the solutions to the equation quadraticformula x^2+15x+50=0 ?
The solutions to the equation quadraticformula x^2+15x+50=0 are x=-5,x=-10
Find the zeros of quadraticformula x^2+15x+50=0
The zeros of quadraticformula x^2+15x+50=0 are x=-5,x=-10