What is the answer to solvefor t,((1+0.1)/(12))^{12t}=2 ?

The answer to solvefor t,((1+0.1)/(12))^{12t}=2 is t=(ln(2))/(12ln(\frac{1.1){12})}

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Solve for t (1+0.10/12)^(12t)=2

solve for

t, (\frac{1 + 0.1}{12})^{12 t} = 2

t = \frac{ln ( 2 )}{12 ln ( \frac{1.1}{12} )}

Decimal Notation

t = - 0.02417 \dots

Solution steps

(\frac{1 + 0.1}{12})^{12 t} = 2

Apply exponent rules

12 t ln (\frac{1 + 0.1}{12}) = ln (2)

Solve

12 t ln (\frac{1 + 0.1}{12}) = ln (2) : t = \frac{ln ( 2 )}{12 ln ( \frac{1.1}{12} )}

t = \frac{ln ( 2 )}{12 ln ( \frac{1.1}{12} )}

0.0 2^{4}

\frac{40}{14}

- \frac{9}{20}

x, ∣ x ∣ = - 16

x, - 10 x = 40

What is the answer to solvefor t,((1+0.1)/(12))^{12t}=2 ?
The answer to solvefor t,((1+0.1)/(12))^{12t}=2 is t=(ln(2))/(12ln(\frac{1.1){12})}