What are the solutions to the equation quadraticformula x^2-5x-2=0 ?

The solutions to the equation quadraticformula x^2-5x-2=0 are x=(5+sqrt(33))/2 ,x=(5-sqrt(33))/2

Find the zeros of quadraticformula x^2-5x-2=0

The zeros of quadraticformula x^2-5x-2=0 are x=(5+sqrt(33))/2 ,x=(5-sqrt(33))/2

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x^{2} - 5 x - 2 = 0

x = \frac{5 + 33}{2}, x = \frac{5 - 33}{2}

Decimal Notation

x = 5.37228 \dots, x = - 0.37228 \dots

Solution steps

x^{2} - 5 x - 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 1 \cdot ( - 2 )}{2 \cdot 1}

(- 5)^{2} - 4 \cdot 1 \cdot (- 2) = 33

x_{1, 2} = \frac{- ( - 5 ) \pm 33}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 33}{2 \cdot 1}, x_{2} = \frac{- ( - 5 ) - 33}{2 \cdot 1}

x = \frac{- ( - 5 ) + 33}{2 \cdot 1} : \frac{5 + 33}{2}

x = \frac{- ( - 5 ) - 33}{2 \cdot 1} : \frac{5 - 33}{2}

The solutions to the quadratic equation are:

x = \frac{5 + 33}{2}, x = \frac{5 - 33}{2}

72 \cdot 7

x, ∣ 3 - 2 x ∣ = 4

8.4%

x, \frac{3}{4} = \frac{x}{8}

14 x^{3}

What are the solutions to the equation quadraticformula x^2-5x-2=0 ?
The solutions to the equation quadraticformula x^2-5x-2=0 are x=(5+sqrt(33))/2 ,x=(5-sqrt(33))/2
Find the zeros of quadraticformula x^2-5x-2=0
The zeros of quadraticformula x^2-5x-2=0 are x=(5+sqrt(33))/2 ,x=(5-sqrt(33))/2