What are the solutions to the equation quadraticformula (x-2)(x-5)=0 ?

The solutions to the equation quadraticformula (x-2)(x-5)=0 are x=5,x=2

Find the zeros of quadraticformula (x-2)(x-5)=0

The zeros of quadraticformula (x-2)(x-5)=0 are x=5,x=2

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(x - 2) (x - 5) = 0

x = 5, x = 2

Solution steps

(x - 2) (x - 5) = 0

Expand

(x - 2) (x - 5) : x^{2} - 7 x + 10

x^{2} - 7 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot 10}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot 10 = 3

x_{1, 2} = \frac{- ( - 7 ) \pm 3}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 3}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 3}{2 \cdot 1}

x = \frac{- ( - 7 ) + 3}{2 \cdot 1} : 5

x = \frac{- ( - 7 ) - 3}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 5, x = 2

\frac{( 2 π )}{( \frac{1}{2} )}

x, 3 x = y

x, 2^{x} = 7

\frac{16}{81}

\frac{100}{25}

What are the solutions to the equation quadraticformula (x-2)(x-5)=0 ?
The solutions to the equation quadraticformula (x-2)(x-5)=0 are x=5,x=2
Find the zeros of quadraticformula (x-2)(x-5)=0
The zeros of quadraticformula (x-2)(x-5)=0 are x=5,x=2