What are the solutions to the equation 5x^2-20x+20=0 ?

The solutions to the equation 5x^2-20x+20=0 are x=2

Find the zeros of 5x^2-20x+20=0

The zeros of 5x^2-20x+20=0 are x=2

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5 x^{2} - 20 x + 20 = 0

x = 2

Solution steps

5 x^{2} - 20 x + 20 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 5 \cdot 20}{2 \cdot 5}

(- 20)^{2} - 4 \cdot 5 \cdot 20 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 5}

x = \frac{- ( - 20 )}{2 \cdot 5}

\frac{- ( - 20 )}{2 \cdot 5} = 2

x = 2

The solution to the quadratic equation is:

x = 2

x^{2} - 14 x - 1 = 0

4 (x - 5) - 6 x \geq x + 4

- 3 x < - 9

\frac{2 ( j ^{2} ) ^{4}}{- 2 j ^{5}}

z^{2} + z - 20

What are the solutions to the equation 5x^2-20x+20=0 ?
The solutions to the equation 5x^2-20x+20=0 are x=2
Find the zeros of 5x^2-20x+20=0
The zeros of 5x^2-20x+20=0 are x=2