What are the solutions to the equation 2x^2-x+6=0 ?

The solutions to the equation 2x^2-x+6=0 are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4

Find the zeros of 2x^2-x+6=0

The zeros of 2x^2-x+6=0 are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

2 x^{2} - x + 6 = 0

x = \frac{1}{4} + i \frac{47}{4}, x = \frac{1}{4} - i \frac{47}{4}

Solution steps

2 x^{2} - x + 6 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 1 ) \pm ( - 1 ) ^{2} - 4 \cdot 2 \cdot 6}{2 \cdot 2}

Simplify

(- 1)^{2} - 4 \cdot 2 \cdot 6 : 47 i

x_{1, 2} = \frac{- ( - 1 ) \pm 47 i}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 1 ) + 47 i}{2 \cdot 2}, x_{2} = \frac{- ( - 1 ) - 47 i}{2 \cdot 2}

x = \frac{- ( - 1 ) + 47 i}{2 \cdot 2} : \frac{1}{4} + i \frac{47}{4}

x = \frac{- ( - 1 ) - 47 i}{2 \cdot 2} : \frac{1}{4} - i \frac{47}{4}

The solutions to the quadratic equation are:

x = \frac{1}{4} + i \frac{47}{4}, x = \frac{1}{4} - i \frac{47}{4}

\frac{9}{5} - \frac{6}{9}

y^{2} - 14 y = - 38

∣ 5 u - 15 ∣ = 10

\frac{3 8}{8 5}

\frac{x - 1}{x + 2} \leq 0

What are the solutions to the equation 2x^2-x+6=0 ?
The solutions to the equation 2x^2-x+6=0 are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4
Find the zeros of 2x^2-x+6=0
The zeros of 2x^2-x+6=0 are x= 1/4+i(sqrt(47))/4 ,x= 1/4-i(sqrt(47))/4