What are the solutions to the equation quadraticformula x^2-6x=40 ?

The solutions to the equation quadraticformula x^2-6x=40 are x=10,x=-4

Find the zeros of quadraticformula x^2-6x=40

The zeros of quadraticformula x^2-6x=40 are x=10,x=-4

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x^{2} - 6 x = 40

x = 10, x = - 4

Solution steps

x^{2} - 6 x = 40

Move

40

to the left side

x^{2} - 6 x - 40 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot ( - 40 )}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot (- 40) = 14

x_{1, 2} = \frac{- ( - 6 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 14}{2 \cdot 1}

x = \frac{- ( - 6 ) + 14}{2 \cdot 1} : 10

x = \frac{- ( - 6 ) - 14}{2 \cdot 1} : - 4

The solutions to the quadratic equation are:

x = 10, x = - 4

- 37 - 45

12 \frac{9}{10}

\frac{( x ^{4} + 36 )}{( x ^{2} - 8 )}

0.8%

b, 30 b + 53 \geq 18 b - 83

What are the solutions to the equation quadraticformula x^2-6x=40 ?
The solutions to the equation quadraticformula x^2-6x=40 are x=10,x=-4
Find the zeros of quadraticformula x^2-6x=40
The zeros of quadraticformula x^2-6x=40 are x=10,x=-4