What are the solutions to the equation quadraticformula x^2-7x-4=0 ?

The solutions to the equation quadraticformula x^2-7x-4=0 are x=(7+sqrt(65))/2 ,x=(7-sqrt(65))/2

Find the zeros of quadraticformula x^2-7x-4=0

The zeros of quadraticformula x^2-7x-4=0 are x=(7+sqrt(65))/2 ,x=(7-sqrt(65))/2

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x^{2} - 7 x - 4 = 0

x = \frac{7 + 65}{2}, x = \frac{7 - 65}{2}

Decimal Notation

x = 7.53112 \dots, x = - 0.53112 \dots

Solution steps

x^{2} - 7 x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 1 \cdot ( - 4 )}{2 \cdot 1}

(- 7)^{2} - 4 \cdot 1 \cdot (- 4) = 65

x_{1, 2} = \frac{- ( - 7 ) \pm 65}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 65}{2 \cdot 1}, x_{2} = \frac{- ( - 7 ) - 65}{2 \cdot 1}

x = \frac{- ( - 7 ) + 65}{2 \cdot 1} : \frac{7 + 65}{2}

x = \frac{- ( - 7 ) - 65}{2 \cdot 1} : \frac{7 - 65}{2}

The solutions to the quadratic equation are:

x = \frac{7 + 65}{2}, x = \frac{7 - 65}{2}

\frac{2}{3}

\frac{75}{36}

x, \frac{2}{3} x = 10

2 x - 3 y

0.4%

What are the solutions to the equation quadraticformula x^2-7x-4=0 ?
The solutions to the equation quadraticformula x^2-7x-4=0 are x=(7+sqrt(65))/2 ,x=(7-sqrt(65))/2
Find the zeros of quadraticformula x^2-7x-4=0
The zeros of quadraticformula x^2-7x-4=0 are x=(7+sqrt(65))/2 ,x=(7-sqrt(65))/2