What is longdivision ((9x^3+3x^2+22x))/((3x^2+1)) ?

The solution to longdivision ((9x^3+3x^2+22x))/((3x^2+1)) is 3x+1+(19x-1)/(3x^2+1)

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Divide Using Long Polynomial Division (9x^3+3x^2+22x)/(3x^2+1)

long division

\frac{( 9 x ^{3} + 3 x ^{2} + 22 x )}{( 3 x ^{2} + 1 )}

3 x + 1 + \frac{19 x - 1}{3 x ^{2} + 1}

Solution steps

\frac{( 9 x ^{3} + 3 x ^{2} + 22 x )}{( 3 x ^{2} + 1 )}

Divide

\frac{9 x ^{3} + 3 x ^{2} + 22 x}{3 x ^{2} + 1} : \frac{9 x ^{3} + 3 x ^{2} + 22 x}{3 x ^{2} + 1} = 3 x + \frac{3 x ^{2} + 19 x}{3 x ^{2} + 1}

= 3 x + \frac{3 x ^{2} + 19 x}{3 x ^{2} + 1}

Divide

\frac{3 x ^{2} + 19 x}{3 x ^{2} + 1} : \frac{3 x ^{2} + 19 x}{3 x ^{2} + 1} = 1 + \frac{19 x - 1}{3 x ^{2} + 1}

= 3 x + 1 + \frac{19 x - 1}{3 x ^{2} + 1}

x, - 4 x < 16

k, 9 (k - 2) = - 6

y, 12 y = 60

y = m x + b, 2 y = 2 x + 4

g, g (0.2) = 0

What is longdivision ((9x^3+3x^2+22x))/((3x^2+1)) ?
The solution to longdivision ((9x^3+3x^2+22x))/((3x^2+1)) is 3x+1+(19x-1)/(3x^2+1)