What are the solutions to the equation quadraticformula 4x^2-5x=0 ?

The solutions to the equation quadraticformula 4x^2-5x=0 are x= 5/4 ,x=0

Find the zeros of quadraticformula 4x^2-5x=0

The zeros of quadraticformula 4x^2-5x=0 are x= 5/4 ,x=0

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4 x^{2} - 5 x = 0

x = \frac{5}{4}, x = 0

Decimal Notation

x = 1.25, x = 0

Solution steps

4 x^{2} - 5 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 4 \cdot 0}{2 \cdot 4}

(- 5)^{2} - 4 \cdot 4 \cdot 0 = 5

x_{1, 2} = \frac{- ( - 5 ) \pm 5}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 5}{2 \cdot 4}, x_{2} = \frac{- ( - 5 ) - 5}{2 \cdot 4}

x = \frac{- ( - 5 ) + 5}{2 \cdot 4} : \frac{5}{4}

x = \frac{- ( - 5 ) - 5}{2 \cdot 4} : 0

The solutions to the quadratic equation are:

x = \frac{5}{4}, x = 0

x, 6 x = 216

x, 3 x - 5 = 16

- 8 x + 10 - 3 x^{2} = - 12 x

- \frac{23}{4}

t, 3 t - 18 = 4 (\frac{- 3 - 3}{4 t})

What are the solutions to the equation quadraticformula 4x^2-5x=0 ?
The solutions to the equation quadraticformula 4x^2-5x=0 are x= 5/4 ,x=0
Find the zeros of quadraticformula 4x^2-5x=0
The zeros of quadraticformula 4x^2-5x=0 are x= 5/4 ,x=0