What are the solutions to the equation quadraticformula 3x^2-7x+4=0 ?

The solutions to the equation quadraticformula 3x^2-7x+4=0 are x= 4/3 ,x=1

Find the zeros of quadraticformula 3x^2-7x+4=0

The zeros of quadraticformula 3x^2-7x+4=0 are x= 4/3 ,x=1

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3 x^{2} - 7 x + 4 = 0

x = \frac{4}{3}, x = 1

Decimal Notation

x = 1.33333 \dots, x = 1

Solution steps

3 x^{2} - 7 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 7 ) \pm ( - 7 ) ^{2} - 4 \cdot 3 \cdot 4}{2 \cdot 3}

(- 7)^{2} - 4 \cdot 3 \cdot 4 = 1

x_{1, 2} = \frac{- ( - 7 ) \pm 1}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- ( - 7 ) + 1}{2 \cdot 3}, x_{2} = \frac{- ( - 7 ) - 1}{2 \cdot 3}

x = \frac{- ( - 7 ) + 1}{2 \cdot 3} : \frac{4}{3}

x = \frac{- ( - 7 ) - 1}{2 \cdot 3} : 1

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = 1

n, 2 - 2 n = 3 n + 17

\frac{x}{( x - 6 )}

x, 3125 = 5^{- 10 + 3 x}

x, 3^{x} = 19

- ∣ 5.5 ∣

What are the solutions to the equation quadraticformula 3x^2-7x+4=0 ?
The solutions to the equation quadraticformula 3x^2-7x+4=0 are x= 4/3 ,x=1
Find the zeros of quadraticformula 3x^2-7x+4=0
The zeros of quadraticformula 3x^2-7x+4=0 are x= 4/3 ,x=1