What are the solutions to the equation quadraticformula 2x^2-2x-12=0 ?

The solutions to the equation quadraticformula 2x^2-2x-12=0 are x=3,x=-2

Find the zeros of quadraticformula 2x^2-2x-12=0

The zeros of quadraticformula 2x^2-2x-12=0 are x=3,x=-2

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2 x^{2} - 2 x - 12 = 0

x = 3, x = - 2

Solution steps

2 x^{2} - 2 x - 12 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 2 ) \pm ( - 2 ) ^{2} - 4 \cdot 2 ( - 12 )}{2 \cdot 2}

(- 2)^{2} - 4 \cdot 2 (- 12) = 10

x_{1, 2} = \frac{- ( - 2 ) \pm 10}{2 \cdot 2}

Separate the solutions

x_{1} = \frac{- ( - 2 ) + 10}{2 \cdot 2}, x_{2} = \frac{- ( - 2 ) - 10}{2 \cdot 2}

x = \frac{- ( - 2 ) + 10}{2 \cdot 2} : 3

x = \frac{- ( - 2 ) - 10}{2 \cdot 2} : - 2

The solutions to the quadratic equation are:

x = 3, x = - 2

x^{2} - 6 x - 7 = 0

x, x^{2} - 2 x = x (2 + x)

1 0^{- 1} = 0.1

15/2 \frac{1}{2}

18 \frac{5}{25}

What are the solutions to the equation quadraticformula 2x^2-2x-12=0 ?
The solutions to the equation quadraticformula 2x^2-2x-12=0 are x=3,x=-2
Find the zeros of quadraticformula 2x^2-2x-12=0
The zeros of quadraticformula 2x^2-2x-12=0 are x=3,x=-2