What are the solutions to the equation completesquare x^2-8x-4=0 ?

The solutions to the equation completesquare x^2-8x-4=0 are x=2sqrt(5)+4,x=-2sqrt(5)+4

Find the zeros of completesquare x^2-8x-4=0

The zeros of completesquare x^2-8x-4=0 are x=2sqrt(5)+4,x=-2sqrt(5)+4

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x^{2} - 8 x - 4 = 0

x = 25 + 4, x = - 25 + 4

Decimal Notation

x = 8.47213 \dots, x = - 0.47213 \dots

Solution steps

x^{2} - 8 x - 4 = 0

Move

4

to the right side

x^{2} - 8 x = 4

Rewrite in the form

(x + a)^{2} = b

(x - 4)^{2} = 20

For

the solutions are

f (x) = a, - a

Solve

x - 4 = 20 : x = 25 + 4

Solve

x - 4 = - 20 : x = - 25 + 4

The solutions to the quadratic equation are:

x = 25 + 4, x = - 25 + 4

x, 5^{x} = \frac{1}{5}

\frac{17}{4}

h, \frac{1}{2} h - 3 = \frac{3}{2} - 3 h

x^{2} + 7 x - 10

x, 8 x^{2} = 3 x

What are the solutions to the equation completesquare x^2-8x-4=0 ?
The solutions to the equation completesquare x^2-8x-4=0 are x=2sqrt(5)+4,x=-2sqrt(5)+4
Find the zeros of completesquare x^2-8x-4=0
The zeros of completesquare x^2-8x-4=0 are x=2sqrt(5)+4,x=-2sqrt(5)+4