What are the solutions to the equation quadraticformula x^2-6x=-5 ?

The solutions to the equation quadraticformula x^2-6x=-5 are x=5,x=1

Find the zeros of quadraticformula x^2-6x=-5

The zeros of quadraticformula x^2-6x=-5 are x=5,x=1

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x^{2} - 6 x = - 5

x = 5, x = 1

Solution steps

x^{2} - 6 x = - 5

Move

5

to the left side

x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 \cdot 1 \cdot 5}{2 \cdot 1}

(- 6)^{2} - 4 \cdot 1 \cdot 5 = 4

x_{1, 2} = \frac{- ( - 6 ) \pm 4}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 4}{2 \cdot 1}, x_{2} = \frac{- ( - 6 ) - 4}{2 \cdot 1}

x = \frac{- ( - 6 ) + 4}{2 \cdot 1} : 5

x = \frac{- ( - 6 ) - 4}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

x = 5, x = 1

a, 7 a = 28

4 \frac{1}{2} %

6.25 \cdot \frac{1}{6}

\frac{16}{3}

x, - 4 > 2 x

What are the solutions to the equation quadraticformula x^2-6x=-5 ?
The solutions to the equation quadraticformula x^2-6x=-5 are x=5,x=1
Find the zeros of quadraticformula x^2-6x=-5
The zeros of quadraticformula x^2-6x=-5 are x=5,x=1