What are the solutions to the equation 3-4x=-6x^2 ?

The solutions to the equation 3-4x=-6x^2 are x= 1/3-i(sqrt(14))/6 ,x= 1/3+i(sqrt(14))/6

Find the zeros of 3-4x=-6x^2

The zeros of 3-4x=-6x^2 are x= 1/3-i(sqrt(14))/6 ,x= 1/3+i(sqrt(14))/6

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3 - 4 x = - 6 x^{2}

x = \frac{1}{3} - i \frac{14}{6}, x = \frac{1}{3} + i \frac{14}{6}

Solution steps

3 - 4 x = - 6 x^{2}

Switch sides

- 6 x^{2} = 3 - 4 x

Move

4 x

to the left side

- 6 x^{2} + 4 x = 3

Move

3

to the left side

- 6 x^{2} + 4 x - 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 6 ) ( - 3 )}{2 ( - 6 )}

Simplify

4^{2} - 4 (- 6) (- 3) : 214 i

x_{1, 2} = \frac{- 4 \pm 2 14 i}{2 ( - 6 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 14 i}{2 ( - 6 )}, x_{2} = \frac{- 4 - 2 14 i}{2 ( - 6 )}

x = \frac{- 4 + 2 14 i}{2 ( - 6 )} : \frac{1}{3} - i \frac{14}{6}

x = \frac{- 4 - 2 14 i}{2 ( - 6 )} : \frac{1}{3} + i \frac{14}{6}

The solutions to the quadratic equation are:

x = \frac{1}{3} - i \frac{14}{6}, x = \frac{1}{3} + i \frac{14}{6}

a, 60 a + 64 \geq 80 a - 92

32 \cdot 6

x, 2^{x} = 49

\frac{( 50 ! )}{( 46 ! )}

\frac{π}{20}

What are the solutions to the equation 3-4x=-6x^2 ?
The solutions to the equation 3-4x=-6x^2 are x= 1/3-i(sqrt(14))/6 ,x= 1/3+i(sqrt(14))/6
Find the zeros of 3-4x=-6x^2
The zeros of 3-4x=-6x^2 are x= 1/3-i(sqrt(14))/6 ,x= 1/3+i(sqrt(14))/6