What are the solutions to the equation factor x^2-48=0 ?

The solutions to the equation factor x^2-48=0 are x=-4sqrt(3),x=4sqrt(3)

Find the zeros of factor x^2-48=0

The zeros of factor x^2-48=0 are x=-4sqrt(3),x=4sqrt(3)

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x^{2} - 48 = 0

x = - 43, x = 43

Decimal Notation

x = - 6.92820 \dots, x = 6.92820 \dots

Solution steps

x^{2} - 48 = 0

Factor

x^{2} - 48 : (x + 43) (x - 43)

(x + 43) (x - 43) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x + 43 = 0 or x - 43 = 0

Solve

x + 43 = 0 : x = - 43

Solve

x - 43 = 0 : x = 43

The solutions to the quadratic equation are:

x = - 43, x = 43

x, 2^{x} = 11

1.17 - 0.07 a + (- 3.92 a)

x, x - 47 = - 25

(2 x - 1) (x + 7)

\frac{3}{10}

What are the solutions to the equation factor x^2-48=0 ?
The solutions to the equation factor x^2-48=0 are x=-4sqrt(3),x=4sqrt(3)
Find the zeros of factor x^2-48=0
The zeros of factor x^2-48=0 are x=-4sqrt(3),x=4sqrt(3)